
证明:过点D作DE//AC交AB于点E.AD是三角形ABC的角平分线.==>角BAD=角CADED//AC==>角ADE=角DAC所以,角ADE=角ABD==>AE=DEED//AC==>BD/DC=BE/EA所以,BD/DC=BE/EDED//AC==>BE/ED=AB/AC所以,BD:DC=AB:AC...

证明:过点D作DE//AC交AB于点E.AD是三角形ABC的角平分线.==>角BAD=角CADED//AC==>角ADE=角DAC所以,角ADE=角ABD==>AE=DEED//AC==>BD/DC=BE/EA所以,BD/DC=BE/EDED//AC==>BE/ED=AB/AC所以,BD:DC=AB:AC...